2018/19 WASSCE FURTHER MATHEMATICS/E MATH QUESTIONS AND ANSWERS BY COOLBOY

*FURTHER MATHS OBJ:*
*F/maths BY COOLBOY*

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*1-10: BCADDDDDBB*
*11-20: DBABCCDDCC*
*21-30: BCABBAABAB*
*31-40: CBADBDDCAB*

*2018 WAEC MAY/JUNE FURTHER MATHS OBJ AND THEORY BY COOLBOY*

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* means multiplication
/ means division

(1)

| x-3  -4  3 |
| 5     2   2 |       = -24
| 2   -4 6-x |

(x-3)[2(6-x) +8]+4[5(6-x) -4]+3(-20-4)  =-24
(x-3)[-2x+20]+4[-5x+26]+3(-24)= -24
-2x^2+26x-60-20x+104-72= -24
-2x^2+6x-4=0
X^2-3x+2=0
X^2-2x-x+2=0
X(x-2)-1(x-2)=0
(x-1)(x-2)=0
X-1=0 OR x-2=0
X=1 OR x=2

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(3a)

U= x-2 ; hence X = u+2
Therefore :
X^3+5/(x-2)^4 = (u+2)^3+5/ (u+2-2)^4
=(u+2)^3+5/u^4

(3b)

(u+2)^3+5/u^4 = (u+2)^3/u^4 + 5/u^4

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(6a)

It follow that:
P(n) = 1/3 and p(k)¹ = 1 - 1/3 = 2/3
P(T) = 1/5 and P(T)¹ = 1- 1/5 = 4/5

Hence,
probability that only one if the them will be solve the questions will be:

= (1/3 × 4/5) + (1/5 × 2/3)
= 4/15 + 2/15
= 6/15
= 2/5

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(7)

m = 3i - 2j ; n = 2i + 3j ; p = i + 6j

Therefore:
4(3i - 2j) +2(2i +3j) -3(-i + 6j)
12i - 8j + 4i + 6j + 3i - 18j
12i + 4i + 3i - 8j + 6j - 18j
19i = 20j

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(8)
m1 = 20kg
u1 = 8ms-1
m2 = 30kg
u2 = 50ms-1

(a)
In same direction
m1u1 + m2u2 = (m1+m2)v
20 × 80 + 30 × 50 = (20+30)v
1600+1500 = 50v
3100/50 = 50/50
V = 62ms-1

(b)
In opposite direction
m1u1 - m2u2 = (m1 + u2)V
20×30 - 30×50 = (20+30)V
1600 - 1500 = 50V
100/50 = 50V/50
V = 2m/s

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