Contact COOLBOY for ur sure and real questions and
before exam..(waec, NPSE,bece, private wassce exam)..
WhatsApp line...08035452768
COOLBOY
TD OBJ
01-10: DBBDADDBCA
11-20: AABBDABDDC
21-30: BCDAAADBCC
31-40: BACADCBBAC
To find the lengths of the other two sides of the triangle, we can use trigonometry. Let's call one of the unknown sides x. Then we know that:
sin(60°) = x/50, since sin(60°) = opposite/hypotenuse in a right triangle with a 60-degree angle.
Rearranging this equation, we get:
x = 50 sin(60°) = 50 × √3/2 = 25√3.
So one of the unknown sides has a length of 25√3, and the other unknown side has the same length, since the triangle is equilateral.
Post a Comment